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Question 1: Represent this markov chain as I-P where P is the stochastic matrix, and I is the identity matrix.
$\begin{bmatrix}1/2&0&1/2&0&0\\0&1&0&0&0\\0&0&1&0&0\\0&0&0&1&0\\0&0&0&0&1\end{bmatrix}$
$\begin{bmatrix}1&-1/2&0&-1/2&0\\0&1&-1&0&0\\0&-1&1&0&0\\0&0&0&1&-1\\0&0&0&-1&1\end{bmatrix}$
$\begin{bmatrix}0&1/2&0&1/2&0\\0&0&1&0&0\\0&1&0&0&0\\0&0&0&0&1\\0&0&0&1&0\end{bmatrix}$
$\begin{bmatrix}1/2&0&-1/2&0&0\\0&1&0&0&0\\0&0&1&0&0\\0&0&0&1&0\\0&0&0&0&1\end{bmatrix}$
Question 2: Set up the system of equations where A is the previous matrix $A\mathbf{x} = \mathbf{b}$, where $\mathbf{x} = [x_1, x_2, x_3, x_4, x_5]^T$ represents the probability of reaching Node 4 starting from each node. Set $\mathbf{b} = [0, 0, 0, 0, 1]^T$ and solve for $\mathbf{x}$.
[1,0,0,1,1]
[1/2,0,0,1,1]
[1,1,1,0,0]
[1/2,1,1,0,0]
Question 3: What does the previous questions' 0 node solution mean for the expected time to get from node 0 to node 4?
It takes an expected 2 steps to reach node 4 from node 0
It is impossible to reach node 4 from node 0
It takes an expected 1/2 steps to reach node 4 from node 0
The expectation will go to infinity as the probability is not 1
Question 4: What property do the two sets which cannot reach each other have when represented as a matrix?
The steps it will take to reach the other set is -1
The nodes probabilities are always 0
The probability of reaching the other set 1
The node sets sum are linearly independent of each other
Question 5: What does this property tell you about probabilities and expectations of the 2 sets of nodes?
The expectation of any node outside of these sets with positive probability for each will be finite
The expectation from one to the other will always be finite
The probability of getting from one set to the other is anywhere from 0 to anything below 1
The expectation of any node outside of these sets with positive probability for each will be undefined
Question 6: Which nodes have a finite expectation towards all other nodes in this new Markov Chain?
Node 0
Every Node
Node 1, Node 0
None
Question 7: How does an extremely low probability differ from 0?
It allows for a defined expectation over time
It has no effect on the Markov Chain
It is effectively the same as 0
It guarantees reaching the state eventually in a finite amount of time
Question 8: Ignore previous markov chains, and consider exclusively the I matrix, can each node represented by this matrix reach the others?
Lower index Nodes can reach higher index nodes
Each node loops to itself
Each node can reach each other
Higher index Nodes can reach lower index nodes
Question 9: What does it mean for expectations if the probability of a node to another is between 0 and 1
The expectation will be finite
The expectation will be undefined
All of the above CAN be true
The expectation will be multiplied by a weight of p the probability
Question 10: What does it mean for expectations if the probability of a node to another is 1
The expectation will be finite
The expectation is always 0
None of the above
The expectation will be undefined
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